IIT JEE Physics Test Paper 6

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IIT JEE Physics Test Paper 6

      IIT JEE Physics Test Paper 6

Part – I (Physics)

This section contains 30 multiple choice questions. Each questions has 4 choices (A), (B), (C) and (D) out of which only one is correct.

1. A car starts from rest and moves with constant acceleration. The ratio of the distance covered in the nth second to that covered in n seconds is:

(A)2/n^2 – 1/n (B)2/n^2 + 1/n (C)2/n – 1/n^2 (D)2/n +1/n^2

2.Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration 2 m/s². If B starts at t = 0 and A starts from the same point at t = 10 s, then the time interval during the journey in which A was ahead of B is:

(A) 20 s (B) 8 s (C) 10 s (D) A is never ahead of B

3.The acceleration of a particle which moves along the positive x-axis varies with its position as shown. If the velocity of the particle is 0.8 m/s at x = 0, the velocity of the particle at x = 1.4 is (in m/s)
6-3

(A) 1.6 (B) 1.2
(C) 1.4 (D) None of these

4.A stone is thrown vertically upward with an initial speed u from the top of a tower, reaches the ground with a speed 3u. the height of the tower is:

 

(A)3U^2/g     (B)4U^2/g    (c)

5.Three particles are projected upward with initial speeds 10 m/s, 20 m/s and 30 m/s. The displacements covered by them in their last second of motion are x1, x2 and x3 then:

(A) x1 : x2 : x3 = 1 : 2 : 3 (B) x1 : x2 : x3 = 1 : 4 : 9
(C) x1 : x2 : x3 = 1 : 5 : 7 (D) None of these

6. A particle moving along a straight line with a constant acceleration of –4 m/s² passes through a point A on the line with a velocity of +8 m/s at some moment. Find the distance travelled by the particle in 5 second after that moment.

(A) 10 (B) 26 (C) 13 (D) 20

7. A moving train is stopped by applying brakes. It stops after travelling 80 m. If the speed of the train is doubled and retardation remain the same, it will cover a distance:

(A) Same as earlier (B) Double the distance covered earlier
(C) Four times the distance covered earlier (D) Half the distance covered earlier

8. A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd seond-

(A)7/5 (B)5/7 (c) 7/3 (D)3/7
9. The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s² . the distance covered by the body in the 5th second of its motion is-

(A) 25 m (B) 35 m (C) 50 m (D) 85 m

10. A coin is released inside a lift at a height of 2 m from the floor of the lift. The height of the lift is 10 m. the lift is moving with an acceleration of 9 m/s² downwards. The time after which the coin will strike with the lift is: (g = 10 m/s²)

(A)4s (B)2s (c)4/sqrt(21)s (D)2/sqrt(11)s

11. A body travelling along a straight line traversed one third of the total distance with a veocity 4 m/s. The remaining part of the distance was covered with a velocity 2 m/s for half the time and with velocity 6 m/s for the other half of time. The mean velocity averaged over the whole time of motion is:

(A) 5 m/s (B) 4 m/s (C) 4.5 m/s (D) 3.5 m/s

12. The displacement of particle moving in a straight line is described by the relation, s = 6 + 12t – 2t². Here s is in metres and t in seconds. The distance covered by particle in first 5 s is:

(A) 20 m (B) 32 m (C) 24 m (D) 26 m

13. A ball is projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6s and the ball reaches the ground after 12s. The height of the tower is (g = 10 m/s²):

(A) 120 m (B) 135 m (C) 175 m (D) 80 m

14. A ball is dropped from the roof of a tower of height h. The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three seconds. The value of h in metres is: (g = 10 m/s²)

(A) 125 (B) 200 (C) 100 (D) 80

15. The acceleration time graph of a particle moving in a straight line is as shown in figure. the velocity of the particle at time t = 0 is 2 m/s. the velocity after 2 s will be:

a(m/s²)
(A) 6 m/s
4
(B) 4 m/s

(C) 2 m/s 1 2 t(s)

(D) 8 m/s

16. A point moves in x-y plane according to the law x = 4 sin 6 t and y = 4(1 – cot 6t). The distance traversed by the particle in 4 s is:

(A) 96 m (B) 48 m (C) 24 m (D) 108 m

17. Velocity versus displacement graph of a particle moving in a straight line is as shown in figure.

The acceleration of the particle is: 

(A) constant (B) increases linearly with x
x
(C) increases parabolically with x (D) None of the above

18. Velocity versus displacement graph of a particle moving in a straight line is shown in figure. Corresponding acceleration versus velocity graph will be:

6-18

6-18-A6-18-B6-18-C
6-18-D

19. Acceleration (A)-displacement (s) graph of a particle moving in a straight line is as shown in figure. The initial velocity of the particle is zero. The v-s graph of the particle would be:

6-19

 

6-19-A 6-19-B 6-19-C6-19-D

 

 

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